3x^2-41x=60

Solution for 3x^2-41x=60 equation:

3x^2-41x=60

We move all terms to the left:

3x^2-41x-(60)=0

a = 3; b = -41; c = -60;
Δ = b2-4ac
Δ = -412-4·3·(-60)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-49}{2*3}=\frac{-8}{6}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+49}{2*3}=\frac{90}{6}
=15
$